Bright Isopropanol
Posted: Wed Jun 07, 2023 6:54 am
Hello,
I have been trying to redo the methanol concentration experiment described on the Pulsar Homepage. However I did not have any methanol and used propanol instead. I get a raman-signal on the camera from both alcohols however I found that the signal comming from the propanol is much stronger than for ethanol. This makes it difficult for me to compare the spectra when I mix both substances since the signal of the propanol will overshadow the signal comming from the ethanol.
When I tried to compute the concentrations the results were widely off with values that were above 1, meaning it is more than pure propanol, negative values etc. I suspect the propanol to be much more fluorecent due to the spectrum that I got.
I do not use the OpenRAMAN software and instead used a python algorythm that I programmed myself. It takes the mean value in each column of pixels as the intensity for this particular wavelength. This helps me avoid hotpixels and noise to some degree.
See my results below: The first image is the spectrum of ethanol, the second one of propanol and the third one compares the two intensities in one graph after background removal (yes I got negative values for some point).
I suspect the propanol to be more fluorecent than the ethanol due to the wide shape of the spectrum. If anyone else has encountred that problem and found a way to solve it I would love to hear about it and exchange ideas.
I have been trying to redo the methanol concentration experiment described on the Pulsar Homepage. However I did not have any methanol and used propanol instead. I get a raman-signal on the camera from both alcohols however I found that the signal comming from the propanol is much stronger than for ethanol. This makes it difficult for me to compare the spectra when I mix both substances since the signal of the propanol will overshadow the signal comming from the ethanol.
When I tried to compute the concentrations the results were widely off with values that were above 1, meaning it is more than pure propanol, negative values etc. I suspect the propanol to be much more fluorecent due to the spectrum that I got.
I do not use the OpenRAMAN software and instead used a python algorythm that I programmed myself. It takes the mean value in each column of pixels as the intensity for this particular wavelength. This helps me avoid hotpixels and noise to some degree.
See my results below: The first image is the spectrum of ethanol, the second one of propanol and the third one compares the two intensities in one graph after background removal (yes I got negative values for some point).
I suspect the propanol to be more fluorecent than the ethanol due to the wide shape of the spectrum. If anyone else has encountred that problem and found a way to solve it I would love to hear about it and exchange ideas.